Question

Find the value of discriminant for $\sqrt{3}{x}^2+2\sqrt{2}x-2\sqrt{3}=0$

Answer 1

Given equation is :

$\sqrt{3}{x}^2+2\sqrt{2}x-2\sqrt{3}=0$

Discriminant = $b^2-4ac$
$a=\sqrt{3}.b=2\sqrt{2},c=-2\sqrt{3}$
$\therefore D=(2\sqrt{2}{)}^2-4(\sqrt{3}\left)\right(-2\sqrt{3})$
$=8+24$
$=32$