Question

Find the value of discriminant for the following equation.

$4x^2-kx+2=0$

• A. $\Delta =k^2-16$
• B. $\Delta =k^2+32$
• C. $\Delta =k^2-32$
• D. $\Delta =k^2+16$

Answer 1

Answer: (C)

$\Delta =k^2-32$

Given equation is:

$4x^2-kx+2=0$

Discriminant = $b^2-4ac$
$a=4,b=-k,c=2$

$\therefore D=(k{)}^2-4(2\left)\right(4)$
$=k^2-32$

$\therefore \Delta =k^2-32$