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Discriminant

Find the valu...

Question

Find the value of discriminant for the following equation.
$x^{2} + 4 x + k = 0$

Δ = 16 + 4 k

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Δ = 16 - 4 k

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Δ = 16 - k

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Δ = 16 + k

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Solution

The correct option is B $Δ = 16 - 4 k$
Given equation is:
$x^{2} + 4 x + k = 0$
Discriminant = $b^{2} - 4 a c$
$a = 1, b = 4, c = k$
$∴ D = (4)^{2} - 4 (k) (1)$
$= 16 - 4 k$
$∴ Δ = 16 - 4 k$

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