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Question

Find the value of discriminant of each of the following equation
3 x2 + 22 x – 23 = 0

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Solution

Given: 3 x2 + 22 x – 23 = 0
On comparing this equation with ax2 + bx + c = 0, we get:
a =3 , b = 22 and c = –23
We know that the discriminant of a quadratic equation is Δ = b2 – 4ac.
Δ = (22 )2 – 4(3 )(–23 )
=> Δ = 8 + 24 = 32

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