Given: x2 – 3x + 2 = 0.
On comparing this equation with ax2 + bx + c = 0, we get:
a = 1, b = –3 and c = 2
We know that the discriminant of a quadratic equation is Δ = b2 – 4ac.
On substituting a = 1, b = –3 and c = 2, we get:
Δ = (–3)2 – 4(1)(2)
=> Δ = 9 – 8 = 1