Find the value of discriminant of each of the following equations.
(i) x² – 3x + 2 = 0.

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Solution

Given: x² – 3x + 2 = 0.
On comparing this equation with ax² + bx + c = 0, we get:
a = 1, b = –3 and c = 2
We know that the discriminant of a quadratic equation is Δ = b² – 4ac.
On substituting a = 1, b = –3 and c = 2, we get:
Δ = (–3)² – 4(1)(2)
=> Δ = 9 – 8 = 1

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