Find the value of discriminant of each of the following equations.
x² + 4x + 1 = 0

Open in App

Solution

Given: x² + 4x + 1 = 0

On comparing this equation with ax² + bx + c = 0, we get:

a = 1, b = 4 and c = 1

We know that the discriminant of a quadratic equation, Δ = b² – 4ac.

On substituting a = 1, b = 4 and c = 1, we get:

Δ = (4)² – 4(1)(1)

$\Rightarrow$ Δ = 16 – 4 = 12

Suggest Corrections

Similar questions

x^{2} + 4 x + k = 0

x^{2} - 4 x + 2 = 0

\sqrt{3}

\sqrt{2}

\sqrt{3}

x^{2} - 4 x + 1 = 0

Find the discriminant of the following quadratic equations $x^{2}$ – x + 1 = 0

Join BYJU'S Learning Program