Find the value of $cos 1^{0} cos 2^{0} cos 3^{0} . . . . . cos 89^{0} . . . . . cos 179^{0} cos 180^{0}$ .

Open in App

Solution

This is the product of the coins of angles ranging from $1^{0}$ to $180^{0}$ within which $cos 90^{0}$ has the value zero
$∴$ the value of the given expression is zero

Suggest Corrections

Similar questions

cos 1^{0} cos 2^{0} cos 3^{0} . . . . . cos 88^{0} cos 89^{0} cos 90^{0}

cos 1^{0} cos 2^{0} cos 3^{0} . . . . cos 179^{0}

cos $1^{o}$ cos $2^{o}$ cos $3^{o}$ ..... cos $180^{o}$ = ?

(a) -1 (b) 1 (c) 0 (d) $\frac{1}{2}$

c o s 1^{0} c o s 2^{^{0}} c o s 3^{0} . . . . . . . . . c o s 180^{0} = 0

(666)^{2}

(66666)^{2}

Join BYJU'S Learning Program