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B
√3−1
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C
12
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D
√2−1
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Solution
The correct option is D√2−1 Given exp. = cosθ−cos3θ+cos4θcosθ−cos3θ+cos4θ =2sin2θsinθ+cos4θ$=2sin2θsinθ+cos4θ [∴θ=45∘][∴θ=45∘] =2sin90∘sin45∘+cos180∘=2sin90∘sin45∘+cos180∘ =2×1×12√−1=2√−1=2×1×12−1=2−1