Question

Find the value of $\frac{-72y^3}{9y}$

• A. $8y^4$
• B. $9y^4$
• C. $8y^2$
• D. $-8y^2$

Answer 1

The correct option is D $-8y^2$

$\frac{-72y^3}{9y}$ = $\frac{-8\times 9y^3}{9y}$=$-8y^{3-1}=-8y^2$