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Question

Find the value of sin48o+cos42ocot42o−1sec48o.

A
sin42o
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B
sin48o
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C
sec48o
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D
cot42o
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Solution

The correct option is A sin42o
Consider, sin48o+cos42ocot42o1sec48o

=sin 48o+cos 42ocos 42osin 42ocos 48o

=sin 48o sin 42o+sin 42o cos42ocos 42o cos 48ocos 42o

=(cos 42o cos 48osin 42o sin 48o)+sin 42o cos 42ocos 42o
=cos 90o+sin 42o cos 42ocos 42o
=sin 42o

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