Question

Find the value of $\frac{\sqrt[3]{327}+\sqrt[3]{3125}}{\sqrt[3]{364}}$

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

The correct option is B $2$

$\sqrt[3]{327}=\sqrt[3]{33\times 3\times 3}=3$

$\sqrt[3]{3125}=\sqrt[3]{35\times 5\times 5}=5$

$\sqrt[3]{364}=\sqrt[3]{34\times 4\times 4}=4$

$\therefore \frac{\sqrt[3]{327}+\sqrt[3]{3125}}{\sqrt[3]{364}}=\frac{3+5}{4}=2$