Find the value of √a+√a+nd√a+√a+d+√a+√a+nd√a+d+√a+2d+…+√a+√a+nd√a+(n−1)d+√a+nd
a+(a+d)+(a+2d)+....+(a+(n−1)d)=n2[2a+(n−1)d]
Let an, nϵN is an A.P. with common difference ′d′ and whose all terms are non-zero. If n approaches infinity, then the sum 1a1a2+1a2a3+...+1anan+1 will approach