Question

Find the value of $\frac{\tan {42}^0+\tan {18}^0}{1-\tan {42}^0\tan {18}^0}+\tan {300}^0$

Answer 1

$\frac{\tan {42}^0+\tan {18}^0}{1-\tan {42}^0\tan {18}^0}+\tan {300}^0$
$=\tan ({42}^0+{18}^0)+\tan ({360}^0-{60}^0)$
$=\tan {60}^0-\tan {60}^0=0$