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Question

Find the value of π20log(tanx)dx.

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Solution

Let I= π20log(tanx)dx........(1).
or, I= π20log(tanπ2x)dx
or, I=π20log(cotx)dx........(2).
Now adding (1) and (2) we get,
2I= π20log(tanx.cotx)dx
or, 2I=0
or, I=0.

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