Find the value of -21-x-xdx-

The correct option is C 1 Now, ∫_ 2^1|x|xdx =∫_ 2^0 xxdx+ ∫_0^1xxdx [ Since |x|= x for x lt;0 ] = ∫_ 2^0 dx+ ∫_0^1 d ...

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Standard XII

Mathematics

Multinomial Expansion

Find the valu...

Question

Find the value of $1 \int - 2 \frac{| x |}{x} d x$ .

0

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- 1

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none of these

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Solution

The correct option is C $- 1$
Now,
$1 \int - 2 \frac{| x |}{x} d x$
$= 0 \int - 2 \frac{- x}{x} d x +$ $1 \int 0 \frac{x}{x} d x$ [ Since $| x | = - x$ for $x < 0$ ]
$= - 0 \int - 2 d x +$ $1 \int 0 d x$
$= - [0 - (- 2)] + 1$
$= - 1$ .

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Find the value of 1∫−2|x|xdx.

The correct option is C −1Now,1∫−2|x|xdx=0∫−2−xxdx+1∫0xxdx [ Since |x|=−x for x<0]=−0∫−2dx+1∫0dx=−[0−(−2)]+1=−1.

Find the value of $1 \int - 2 \frac{| x |}{x} d x$ .

The correct option is C $- 1$
Now,
$1 \int - 2 \frac{| x |}{x} d x$
$= 0 \int - 2 \frac{- x}{x} d x +$ $1 \int 0 \frac{x}{x} d x$ [ Since $| x | = - x$ for $x < 0$ ]
$= - 0 \int - 2 d x +$ $1 \int 0 d x$
$= - [0 - (- 2)] + 1$
$= - 1$ .