Find the value of 1∫−2|x|xdx.
If ω≠1 is a cube root of unity and ∣∣ ∣ ∣∣x+ω2ω1ωω21+x1x+ωω2∣∣ ∣ ∣∣=0, then value of x is
The complete set of values of 'a' such that x2+ax+a2+6a < 0 ∀ x ϵ [-1, 1] is: