Find the value of 3x 3 - 2x 2 -x - 4x

The correct option is C 1 / 4 ( 3x ^ 2 +2x+1 ) #160;( 3x ^ 3 + 2x ^ 2 +x ) ÷ 4x= 3x ^ 3 + 2x ^ 2 +x / 4x #160; #160;= x( 3x ^ 2 +2x+1 ) ...

You visited us 10 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Division of a Polynomial by a Monomial

Find the valu...

Question

Find the value of $({3 x}^{3} + {2 x}^{2} + x) \div 4 x$

{3 x}^{2} + 2 x + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{4} ({3 x}^{2} + 2 x + 1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{3 x}^{2} + 2 x + \frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x + 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1}{4} ({3 x}^{2} + 2 x + 1)$
$({3 x}^{3} + {2 x}^{2} + x) \div 4 x = \frac{{3 x}^{3} + {2 x}^{2} + x}{4 x}$

$= \frac{x ({3 x}^{2} + 2 x + 1)}{4 x}$

$= \frac{1}{4} ({3 x}^{2} + 2 x + 1)$

Suggest Corrections

Similar questions

Q. Simplify:
(x³ − 2x² + 3x − 4) (x −1) − (2x − 3)(x² − x + 1)

Find the discriminant of each of the following equations :
(i) $2 x^{2} - 7 x + 6 = 0$ (ii) $3 x^{2} - 2 x + 8 = 0$
(iii) $2 x^{2} - 5 \sqrt{2} x + 4 = 0$ (iv) $\sqrt{3} x^{2} + 2 \sqrt{2} x - 2 \sqrt{3} = 0$
(v) $(x - 1) (2 x - 1) = 0$ (vi) $1 - x = 2 x^{2}$

Q. (i) Simplify:

(x^{3} - 2 x^{2} + 3 x - 4) (x - 1) - (2 x - 3) (x^{2} - x + 1)

(ii) Simplify:

x^{2} (x - y) y^{2} (x + 2 y)

Q. Find

3 x^{2} - 4 x + 2 = 2 x^{2} - 2 x + 4

Q. Multiply:

(\frac{1}{3} x^{2} - \frac{1}{2} x + 5)

(\frac{1}{2} x^{2} - \frac{1}{3} x + 1)

Join BYJU'S Learning Program

Find the value of (3x3+2x2+x)÷4x

The correct option is C 14(3x2+2x+1)(3x3+2x2+x)÷4x=3x3+2x2+x4x=x(3x2+2x+1)4x=14(3x2+2x+1)

Find the value of $({3 x}^{3} + {2 x}^{2} + x) \div 4 x$

The correct option is C $\frac{1}{4} ({3 x}^{2} + 2 x + 1)$
$({3 x}^{3} + {2 x}^{2} + x) \div 4 x = \frac{{3 x}^{3} + {2 x}^{2} + x}{4 x}$

$= \frac{x ({3 x}^{2} + 2 x + 1)}{4 x}$

$= \frac{1}{4} ({3 x}^{2} + 2 x + 1)$