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Question

Find the value of (7a68a5+9a4)÷a3

A
7a38a2+9a
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B
7a28a+9
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C
7a48a2+9a
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D
7a28a2+9a
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Solution

The correct option is B 7a38a2+9a
(7a68a5+9a4)÷a3=7a68a5+9a4a3

=a3(7a38a2+9a)a3

=7a38a2+9a

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