Find the value of a - b-1 - a - b-1 2 - a - b-1 3 if a-2b-2-

The correct option is C 6 a+2b=2 #160; #160; ...Given a= 2(b 1) #160; #160;....(1)So, (ab 1)+ (ab 1)^2+ (ab 1)^3 ...

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Byju's Answer

Standard XII

Mathematics

Properties of Iota

Find the valu...

Question

Find the value of $(\frac{a}{b - 1}) + {(\frac{a}{b - 1})}^{2} + {(\frac{a}{b - 1})}^{3}$ if $a + 2 b = 2$ .

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Solution

The correct option is C $- 6$
$a + 2 b = 2$ ...Given
$a = - 2 (b - 1)$ ....(1)
So, $(\frac{a}{b - 1}) +$ ${(\frac{a}{b - 1})}^{2} +$ ${(\frac{a}{b - 1})}^{3}$

$= (- 2) + (- 2)^{2} + (- 2)^{3}$
$= - 2 + 4 - 8$
$= - 6$

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Find the value of (ab−1)+(ab−1)2+(ab−1)3 if a+2b=2.

The correct option is C −6a+2b=2 ...Givena=−2(b−1) ....(1)So, (ab−1)+(ab−1)2+(ab−1)3=(−2)+(−2)2+(−2)3=−2+4−8=−6

Find the value of $(\frac{a}{b - 1}) + {(\frac{a}{b - 1})}^{2} + {(\frac{a}{b - 1})}^{3}$ if $a + 2 b = 2$ .

The correct option is C $- 6$
$a + 2 b = 2$ ...Given
$a = - 2 (b - 1)$ ....(1)
So, $(\frac{a}{b - 1}) +$ ${(\frac{a}{b - 1})}^{2} +$ ${(\frac{a}{b - 1})}^{3}$

$= (- 2) + (- 2)^{2} + (- 2)^{3}$
$= - 2 + 4 - 8$
$= - 6$