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Question

Find the value of:
(aman)mn×(ana1)n1×(a1am)1m

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Solution

We have (aman)mn×(ana1)n1×(a1am)1m

By using law aman=amn

=(am+n)mn×(an+1)n1×(am+1)1m

=am2n2×an212×a12m2
By using law am×an=am+n

=am2n2+n21+1m2
=a0
=1

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