Question

Find the value of $\log \frac{9}{8}-\log \frac{27}{32}+\log \frac{3}{4}$

Answer 1

Given $\log \frac{9}{8}-\log \frac{27}{32}+\log \frac{3}{4}$

$=\log (\frac{9}{8}÷\frac{27}{32})+\log \frac{3}{4}$
$=\log (\frac{9}{8}\times \frac{32}{27}\times \frac{3}{4})$

$=\log 1=0$
$[\because {\log }_{a}1=0]$