Find the value of $sin 240^{\circ}$

- \frac{\sqrt{3}}{2}

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+ \frac{\sqrt{3}}{2}

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- \frac{\sqrt{5}}{2}

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- \frac{\sqrt{3}}{4}

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Solution

The correct option is A $- \frac{\sqrt{3}}{2}$
$sin 240^{\circ} = sin (270^{\circ} - 30^{\circ}) = - cos 30^{\circ} = - \frac{\sqrt{3}}{2}$
Using Identity $[sin (270^{\circ} - θ) = - cos θ]$

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