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Byju's Answer
Standard XII
Mathematics
Property 7
Find the valu...
Question
Find the value of
tan
−
1
√
3
−
sec
−
1
(
−
2
)
is equal to
A
π
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B
−
π
3
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C
π
3
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D
2
π
3
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Solution
The correct option is
A
−
π
3
The value of
tan
−
1
√
3
−
sec
−
1
(
−
2
)
=
π
3
−
sec
−
1
(
sec
(
π
−
π
3
)
)
=
π
3
−
2
π
3
=
−
π
3
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