Question

Find the value of $x+y$ in the above figure, if $z={50}^o$.

• A. ${90}^o$
• B. ${130}^o$
• C. ${180}^o$
• D. ${210}^o$
• E. ${230}^o$

Answer 1

The correct option is E ${230}^o$

The interior angles of the triangle are $({180}^0-x),({180}^0-y),z$ since $x$ and $y$ form linear pairs.

Therefore sum of interior angle of the triangle is ${180}^0$.

Hence ${180}^0-x+{180}^0-y+z={180}^0$

$\Rightarrow {360}^0-(x+y)+z={180}^0$

$\Rightarrow {180}^0+z=(x+y)$

$\Rightarrow {180}^0+{50}^0=(x+y)$

$\Rightarrow (x+y)={230}^0$