Question

Find the value of $y+z$ given that:

$3x+2y+2z=19$ and
$3x+y+z=14$

• A. $-5$
• B. $-4$
• C. $0$
• D. $4$
• E. $5$

Answer 1

The correct option is E $5$

Let $3x+2y+2z=19$ ....(i)

and $3x+y+z=14$ ....(ii)

Subtracting equation (ii) from (i) gives us
$(3x+2y+2z)-(3x+y+z)=19-14$

$y+z=5$

Hence the required answer is $5$.