Find the value of $e^{i 2 π}$ .

___

Open in App

Solution

We know $e^{i θ} = c o s θ + i s i n θ$
$e^{i 2 π} = c o s 2 π + i s i n 2 π$
Substitute the value of $c o s 2 π$ & $s i n 2 π$
= 1 + 0
=1

Suggest Corrections

Similar questions

Find the value of $e^{i 2 π}$ .

ω

= e^{i 2 π / 3}

a, b, c, x, y, z

a + b + c = x

a + b ω + c ω^{2} = y

a + b ω^{2} + c ω = z

\frac{| x |^{2} + | y |^{2} + | z |^{2}}{| a |^{2} + | b |^{2} + | c |^{2}}

a = e^{i \frac{2 π}{13}}

α = a + a^{3} + a^{4} + a^{- 4} + a^{- 3} + a^{- 1}, β = a^{2} + a^{5} + a^{6} + a^{- 6} + b^{- 5} + a^{- 2}

a x^{2} + b x + c = 0

α = z^{2} + z^{4} + . . . . . + z^{2 n}

β = z + z^{3} + . . . . . + z^{2 n - 1}

z = e^{i ⎛ ⎝ \frac{2 π}{2 n + 1} ⎞ ⎠}, n \in N,

(666)^{2}

(66666)^{2}

Join BYJU'S Learning Program