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Question

Find the value of each of the following [4 MARKS]

(i)(5)12×(5)32

(ii)(7)43×(7)23

(iii)4×(9)52×(9)32

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Solution

Concept: 1 Mark
Application: 1 Mark each

(i)(5)12×(5)32

=(5)12+32 [Using:xa×xb=xa+b]

=(5)1+32

=(5)42

=(5)2

=5×5=25


(ii)(7)43×(7)23

​​​​​​ =(7)43+23 [Using:xa×xb=xa+b]

=(7)63

=72
=7×7
=49


(iii)4×(9)52×(9)32

=4×(9)52+(32) [Using:xa×xb=xa+b]

=4×(9)5232

=4×(9)532

=4×922

=4×9

=36

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