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Question

Find the value of n(10et2+t(2t2+t+1)dt)

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Solution

10et2+t(2t2+t+1)dt=101.et2+tdt+10et2+t(2t2+t)dt=[t.et2+t]1010et2+t(2t+1)(t)dt+10et2+t(2t2+t)dt=e2
ln(10et2+t(2t2+t+1)dt=ln(e2)=2

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