wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of k for which the following system of equations has a unique solution:
4x+ky+8=0x+y+1=0

Open in App
Solution

The given system of equations is
4x+ky+8=0 .....ix+y+1=0 .....ii
This system is of the form
a1x+b1y+c1=0a2x+b2y+c2=0
where a1=4, b1=k, c1=8 and a2=1, b2=1, c2=1
For the given system of equations to have a unique solution, we must have
a1a2b1b241k1k4
Hence, k4.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Framing a Linear Equation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon