Find the value of $f (x) = x^{4} + 3 x^{3} + 2 x^{2} + 1$ if $x = 2$ .

Open in App

Solution

$f (x) = x^{4} + 3 x^{3} + 2 x^{2} + 1 f (2) = 2^{4} + 3 (2)^{3} + 2 (2)^{2} + 1 f (2) = 16 + 24 + 8 + 1 = 49$

Suggest Corrections

Similar questions

x = ω - ω^{2} - 2,

x^{4} + 3 x^{3} + 2 x^{2} - 11 x - 6

ω

x = ω - ω^{2} - 2

x^{4} + 3 x^{3} + 2 x^{2} - 11 x - 6.

x^{4} - 3 x^{3} + 2 x^{2} + x - 1

(x - 2)

f (x) = x^{4} - 3 x^{3} + 3 x^{2} - x

x^{4} + 1 - 3 (x^{3} + x) = 2 x^{2}

Join BYJU'S Learning Program