Find the value of following polynomial by taking $x = 1, y = 3$ :
$2 x^{2} - x + 2$

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Solution

The correct option is A $3$
We simply substitute $x = 1, y = 3$ in the given polynomial $2 x^{2} - x + 2$ as shown below:

$2 x^{2} - x + 2 = 2 (1)^{2} - 1 + 2 = (2 \times 1) + 1 = 2 + 1 = 3$

Hence, the value of the polynomial $2 x^{2} - x + 2 = 3$ when $x = 1, y = 3$ .

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Similar questions

Q. Find the value of following polynomial by taking

x = 1, y = 3

y^{2} - x y + y

Q. Find the value of following polynomials by taking x = 1, y = 3 and a = 2:

x^{3} + y^{2}

Q. Find the value of following polynomial by taking

x = 1

and

a = 2

3 x^{4} - a x^{3} + 5 x - 3

Find the value of each given polynomial at the given value of its variable :
(i) $5 x^{2} - 7 x + 2$ at x = 2
(ii) $x^{2} + 15 x - 4$ at x = -3
(iii) $3 y + 8 - 2 y^{2}$ at y = –3
(v) $x^{2} + 3 x + 1$ at x = -1/3
(v) $x^{3} - 3 x^{2} + 5 x + 2$ at x = – 1

Divide the first polynomial by the second polynomial in each of the following, Also, write the quotient and remainder.

(i) $3 x^{2} + 4 x + 5, x - 2$

(ii) $10 x^{2} - 7 x + 8, 5 x - 3$

(iii) $5 y^{2} - 6 y^{2} + 6 y - 1, 5 y - 1$

(iv) $x^{4} - x^{3} + 5 x, x - 1$

(v) $y^{4} + y^{2}, y^{2} - 2$

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Find the value of following polynomial by taking x=1,y=3:2x2−x+2

The correct option is A 3We simply substitute x=1,y=3 in the given polynomial 2x2−x+2 as shown below:2x2−x+2=2(1)2−1+2=(2×1)+1=2+1=3Hence, the value of the polynomial2x2−x+2=3 when x=1,y=3.

Find the value of following polynomial by taking $x = 1, y = 3$ :
$2 x^{2} - x + 2$

The correct option is A $3$
We simply substitute $x = 1, y = 3$ in the given polynomial $2 x^{2} - x + 2$ as shown below:

$2 x^{2} - x + 2 = 2 (1)^{2} - 1 + 2 = (2 \times 1) + 1 = 2 + 1 = 3$

Hence, the value of the polynomial $2 x^{2} - x + 2 = 3$ when $x = 1, y = 3$ .