Find the value of 1−tan2 30∘1+tan2 30∘.
0.5
1
2
4
We know that tan 30∘=1√3.
⇒1−tan2 30∘1+tan2 30∘=1−(1√3)21+(1√3)2
=1−(13)1+(13)
=3−13+1
=24 = 12=0.5