Question

Find the value of $\frac{{10}^{22}+{10}^{20}}{{10}^{20}}$.

• A. ${10}^{42}$
• B. $10$
• C. ${10}^2$
• D. $101$

Answer 1

The correct option is D $101$

$\frac{{10}^{22}+{10}^{20}}{{10}^{20}}=({10}^{22}+{10}^{20})\times {10}^{-20}(\because \frac{1}{a^m}=a^{-m})=({10}^{22}\times {10}^{-20})+({10}^{20}\times {10}^{-20})={10}^{22-20}+{10}^{20-20}(\because a^m\times a^n=a^{m+n})={10}^2+{10}^0=100+1(\because a^0=1)$
$=101$