Find the value of -2-57 - -2-52-

According to the laws of exponents, a^b ÷ a^c = a^b c nbsp;, where 'a' is a non zero integer. Using this law, we get, ( 2/5)^7 ÷ ( 2/5)^2= ( 2/5)^7 2 =( 2 ...

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Standard VIII

Mathematics

Negative Exponents

Find the valu...

Question

Find the value of $(\frac{- 2}{5})^{7} \div (\frac{- 2}{5})^{2} .$

- \frac{2}{5}

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\frac{2}{5}

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(- \frac{2}{5})^{5}

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\frac{- 8}{125}

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Solution

The correct option is C $(- \frac{2}{5})^{5}$
According to the laws of exponents,

$a^{b} \div a^{c} = a^{b - c}$ , where 'a' is a non-zero integer.

Using this law, we get,

$(\frac{- 2}{5})^{7} \div (\frac{- 2}{5})^{2} = (\frac{- 2}{5})^{7 - 2}$

$= (\frac{- 2}{5})^{5}$

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Find the value of (−25)7÷(−25)2.

The correct option is C (−25)5According to the laws of exponents, ab÷ac=ab−c , where 'a' is a non-zero integer. Using this law, we get, (−25)7÷(−25)2=(−25)7−2 =(−25)5

Find the value of $(\frac{- 2}{5})^{7} \div (\frac{- 2}{5})^{2} .$

The correct option is C $(- \frac{2}{5})^{5}$
According to the laws of exponents,

$a^{b} \div a^{c} = a^{b - c}$ , where 'a' is a non-zero integer.

Using this law, we get,

$(\frac{- 2}{5})^{7} \div (\frac{- 2}{5})^{2} = (\frac{- 2}{5})^{7 - 2}$

$= (\frac{- 2}{5})^{5}$