Question

Find the value of $(\frac{-2}{5}{)}^7÷(\frac{-2}{5}{)}^6$.

• A. $(\frac{-2}{5}{)}^2$
• B. $\frac{2}{5}$
• C. $\frac{-2}{5}$
• D. $\frac{4}{5}$

Answer 1

The correct option is C

$\frac{-2}{5}$

$\frac{a^b}{a^c}=a^{b-c}$ [a is a non-zero integer]

Using this law, we get,

$(\frac{-2}{5}{)}^7÷(\frac{-2}{5}{)}^6$

${\left(\frac{-2}{5}\right)}^{7-6}={\left(\frac{-2}{5}\right)}^1=\frac{-2}{5}$