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Question

Find the value of
4(216)23+1(256)34+2(243)15

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Solution

We have,
4(216)23+1(256)34+2(243)15

=4(63)23+1(162)34+2(35)15 [216=63,256=162,243=35]=463×(23)+1162×(34)+235×(15) [(am)n=amn]=462+11632+231=4×62+1632+2×31 [1a=a1]=4×36+((4)2)3/2+2×31=4×36+43+6=144+64+6=214

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