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Question

Find the value of 433+47343243× 47+472 using a suitable algebraic identity.
  1. 90

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Solution

The correct option is A 90
Using the identity a3+b3=(a2ab+b2)(a+b)
On taking a=43 and b=47,
the given expression becomes:
a3+b3a2ab+b2=a+b

433+47343243× 47+472

=43+47
=90.

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