Find the value of (a2 + 2a)2a + 5 if 'a' can have values 6, 16.
9
14
The algebraic fraction : (a2 + 2a)2a + 5
⇒ a×(a + 2)2a + 5
On canceling the common factor 'a',
⇒ (a + 2)2 + 5
⇒if a = 6: (6 + 2)2 + 5 = 9
Also, if a = 16: (16 + 2)2 + 5 = 14
So, answers are 9 and 14.