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Question

Find the value of sin 50ocos 40o+cosec 40osec 50o4 cos 50o cosec 40o.

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Solution

As we know

sin50o=sin(9040)=cos50o

cosec40o=cosec(9050)=sec40o

cos50o=cos(9040)=sin40o

sin40o cosec40o=1

now put these values in this,

sin 50ocos 40o+cosec 40osec 50o4 cos 50o cosec 40o

and we get,


fraction numerator cos 40 over denominator cos 40 end fraction plus fraction numerator s e c 50 over denominator s e c 50 end fraction minus 4 sin 40 cos e c 40 1 plus 1 minus 4 equals negative 2


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