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Question

Find the value of : xa(b c)xb(a c) ÷ (xbxa)c


A

a

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B

0

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C

b

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D

1

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Solution

The correct option is D

1


xa(b c)xb(a c) ÷ (xbxa)c

=x(ab ac)x(ba bc) ÷ (xbxa)c

=(xab ac ab + bc) ÷ (xb a)c
[(am)(an) = amn]

=xab ac ab + bc ÷ xbc ac
[(am)n=(a)m×n]

=xab ac ab + bcxbc ac

=xab ac ab + bc bc + ac
[(am)(an) = amn]=x0

=1 [a0=1, a0]


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