Question

FInd the value of $h$ in the equation: $\frac{3(h+2)-4}{6}=\frac{h(7\times 2-5)}{2}$.

• A. $\frac{1}{12}$
• B. $\frac{1}{6}$
• C. $\frac{1}{2}$
• D. $\frac{1}{3}$

Answer 1

The correct option is A $\frac{1}{12}$

Given, $\frac{3(h+2)-4}{6}=\frac{h(7\times 2-5)}{2}$

$\Rightarrow \frac{3h+6-4}{6}=\frac{h(14-5)}{2}$

$\Rightarrow \frac{3h+2}{6}=\frac{9h}{2}$

$\Rightarrow 6h+4=54h$ …[Cross-multiplying the denominators].

Transposing $h$ terms to one side, we get,

$\Rightarrow 6h-54h=-4$

$\Rightarrow -48h=-4$

$\Rightarrow h=\frac{-4}{-48}=\frac{1}{12}$.

Hence, option $A$ is correct.