Find the value of:
(i)26(ii)93(iii)112(iv)54
Solve for the required values
(i) 26
We know that an=a×a×a×.........(ntimes)
∴26=2×2×2×2×2×2=64
(ii) 93
∴93=9×9×9=729
(iii) 112
∴112=11×11=121
(iv) 54
∴54=5×5×5×5=625
Hence the values are
(i) 26=64
(ii) 93=729
(iii) 112=121
(iv) 54=625
(i) 26 (ii) 93
(iii) 112 (iv)54
Mention the value of the variable in each of the following:
(1)
(2)
(3)
(4)
(5)