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Question

Find the value of:

(i)26(ii)93(iii)112(iv)54


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Solution

Solve for the required values

(i) 26

We know that an=a×a×a×.........(ntimes)

26=2×2×2×2×2×2=64

(ii) 93

We know that an=a×a×a×.........(ntimes)

93=9×9×9=729

(iii) 112

We know that an=a×a×a×.........(ntimes)

112=11×11=121

(iv) 54

We know that an=a×a×a×.........(ntimes)

54=5×5×5×5=625

Hence the values are

(i) 26=64

(ii) 93=729

(iii) 112=121

(iv) 54=625


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