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Question

Find the value of:
(i) (30+41)×22

(ii) (21×41)÷22

(iii) (12)2+(13)2+(14)2

(iv) (31+41+51)0

(v) [(23)2]2

(vi) 720721

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Solution

(i) (30+41)×22=(1+14)×4

=(54)×4

=5

(ii) (21×41)÷22=(12×14)×22

=(12×14)×4

=12

(iii) (12)2+(13)2+(14)2=22+32+42

=4+9+16

=29

(iv) (31+41+51)0=(13+14+15)0

=1 a0=1

(v) [(23)2]2=(23)4

=(32)4

=8116

(vi) 720721=17201721

=1720(117)

=1720(67)

=6721



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