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Question

Find the value of:
(i) (6)/23
(ii) 45/2
(iii) 313/(465)
(iv) 28/28

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Solution

(i) (6)/23=61×32=6×31×2=182=9
So, (6)/23=9

(ii) 45/2=45×12=4×15×2=2×15=25
So, 45/2=25

(iii) 313/(465)=313×654=3×6513×(4)=154=154
So, 313/465=154

(iv) 28/28=28×82=(2)×88×(2)=1×11×1=1
So, 28/28=1

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