Question

Find the value of $‘I^{\prime }$ for the following circuit.

• A. $1A$
• B. $10A$
• C. $\frac{1}{16}A$
• D. $\frac{1}{8}A$

Answer 1

The correct option is A $1A$

Since all the resistors are placed in parallel combination, so the equivalent resistance of the system will become

$\frac{1}{R_{eq}}=\frac{1}{140}+\frac{1}{140}+\frac{1}{140}+\frac{1}{140}$
$\Rightarrow R_{eq}=\frac{140}{4}=35\Omega$
Now applying Ohm’s law: $V=I\times R_{eq}$
$\Rightarrow I=\frac{V}{R_{eq}}=\frac{35}{35}=1A$