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Question

Find the value of
i)log232 ii)log535
iii)log264 iv)log10100000

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Solution

# (i)log232=x
32=2x x=5
(ii)log535=x
35=5x(5)1/3=5x
x=1/3
(iii)log264=x
64=(2)x64=2x/2
x=14
(iv)log10100000=x10,0000=10x
x=5

1100546_1180214_ans_4e0936c7a87a456e8a160d965f12edbb.jpg

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