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Question

Find the value of 11[x2+{x}]dx, where [] and {} denote the greatest function and fractional parts of x, respectively.

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Solution

A] To find period of
f(x)=sin3xcos[3x]cos3xsin[3x]
As
sin(AB)=sinAcosBcosAsinB
So, sin3xcos[3x]cos3xsin[3x]
=sin(3x[3x])
As x[x]={x}
So, sin(3x[3x])
=sin({3x})
The period of fractional part of
x is 0 to 1
so, period of
f(x)=sin{3x}
is 13

1152696_697013_ans_bf550d2222db44e7b2693130e10d9db0.jpg

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