Find the value of k1 and k2 for which →V can be represented as →V=k1→A+k2→B. Where, →V=2i−j , →A=3i−2j and →B=3i+3j.
A
k1=1 and k2=1
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B
k1=35andk2=12
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C
k1=−23andk2=25
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D
k1=35andk2=115
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Solution
The correct option is Dk1=35andk2=115 The vector →V can be expressed as→V=k1→A+k2→B 2i−j=k1(3i−2j)+k2(3i+3j) ⇒2i−j=(3k1+3k2)i+(−2k1+3k2)j
Equating terms from both sides ⇒2=(3k1+3k2) ⇒−1=(−2k1+3k2)
Solving both the equations we get k1=35 and k2=115