Find the value of $k_{1}$ if $x = 2, y = 2$ it a solution equation $2 x + 3 y = k$ . find two more solution as resultant equation.

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Solution

Given, $x = 2, y = 2$

Equation = $2 x + 3 y = K . . . . . . . . . .1$

Put the value of x and y in equation 1 then we get

$K = 2 \times 2 + 3 \times 2 = 10$

Now If $x = - 2$ and $y = - 2$ then, equation becomes $K = (- 2) \times 2 + 3 \times (- 2) = - 10$

If $x = 0, y = 0$ then, equation 1 becomes $K = 0 + 0 = 0$

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