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Question

Find the value of k
3k310k2+9k2=0

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Solution

Given 3k310k2+9k2=0=p(x)
when k=1 p(x)=0
Synthetic division
(k1)(3k27k+2)
(k1)(3k26kk+2)
(k1)[3k(k2)1(k2)]
(k1)(3k1)(k2)
values of k are
k=13,1,2

1348260_1231650_ans_88cb1f24cb9a46e7a4e791b7a5a4fc3a.PNG

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